If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x^2+6x-396=0
a = 1; b = 6; c = -396;
Δ = b2-4ac
Δ = 62-4·1·(-396)
Δ = 1620
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1620}=\sqrt{324*5}=\sqrt{324}*\sqrt{5}=18\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-18\sqrt{5}}{2*1}=\frac{-6-18\sqrt{5}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+18\sqrt{5}}{2*1}=\frac{-6+18\sqrt{5}}{2} $
| x^2+4x-264=0 | | 10x+15(12-x)=0 | | 5(m-5)+4=39 | | x÷4=29 | | 2x+2*(x*(1/3))=40 | | -5x-21=13 | | 20-1y+2y=40 | | 5m-3m+8m=70 | | 2x²-8+8=0 | | 11x-3x^2=22 | | (X+3)8=10x | | 0,5^-x=243 | | x=(100*180)/(100+25) | | 88–4y=56 | | 180=x((100+25)/100) | | x=180/30 | | 180=x+250/100*x | | x4/4x=0 | | x=(180*100)/(100+25/100) | | x=(180*100)/(100+25) | | 180=x+25/100*x | | 12w=-198 | | 5×(x^2-1)=4×(x^2+1) | | x+3x-2x+4x-36=0 | | 1/2x-7=-2/3x | | 2(2x−1)+2x=6 | | Y2-5y+11=0 | | 5(x+3)=25(x+5) | | -7x2+3x+6=0 | | 32-x=2x+7 | | 5x-1=7x4 | | 10x2-5x+10=0 |